935A - Fafa and his Company - CodeForces Solution

brute force implementation *800

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Python Code: 

n =int(input())
count =0
for i in range(1,n):
    if n%i==0:
        count =count +1
print(count)

C++ Code: 

#include<bits/stdc++.h>
using namespace std;

int main(){

    int n;
    cin>>n;

    int count = 0;

    for(int i=1;i<=n/2;i++){

        if ((n-i)%i==0) count++;

    }

    cout << count ;

    return 0;
}


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